An inductor of 20 mH, a capacitor of 50  and a resistor of 40 ohm are connected in series across a source of emf V = 10 sin 340 t. the power loss in the ac circuit is,

• 0.67 W

• 0.76 W

• 0.89 W

• 0.89 W

A small signal voltage V(t) = V_o sin  is applied across an ideal capacitor C:

• over a full cycle the capacitor C does not consume any energy from the voltage source

• current I(t) is in phase with voltage V(t)

• Current I(t) leads voltage V(t) by 180^o

• Current I(t) leads voltage V(t) by 180^o

The output of a step down transformers is measured to be 48 V when connected to a 12 W bulb. The value of peak current is

• $\frac{1}{\sqrt{2}} \mathrm{A}$

• $\sqrt{2} \mathrm{A}$

• $\frac{1}{2\sqrt{2}} \mathrm{A}$

• $\frac{1}{4} \mathrm{A}$

A resistance 'R' draws power 'P' when connected to an AC source. If an inductance is now placed in series with the resistance such that the impedance of the circuit becomes 'Z' the power drawn will be

In the circuit shown in the figure, the AC source gives a voltage V = 20 cos (2000t). Neglecting source resistance, the voltmeter and ammeter reading will be

• 1.68 V, 0.47 A

• 0 V, 1.47 A

• 5.6 V, 1.4 A

• 0 V, 1.4 A